3000x+3000x^2=180

Solution for 3000x+3000x^2=180 equation:

3000x+3000x^2=180

We move all terms to the left:

3000x+3000x^2-(180)=0

a = 3000; b = 3000; c = -180;
Δ = b2-4ac
Δ = 30002-4·3000·(-180)
Δ = 11160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11160000}=\sqrt{360000*31}=\sqrt{360000}*\sqrt{31}=600\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3000)-600\sqrt{31}}{2*3000}=\frac{-3000-600\sqrt{31}}{6000}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3000)+600\sqrt{31}}{2*3000}=\frac{-3000+600\sqrt{31}}{6000}
$